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    ÎÒ¹ú´óÁ¿Éú²úʵ¼ùÖ¤Ã÷,ÉÏÊöÁ÷³ÌÊÕÂʸß,²úÆ·ÖÊÁ¿ºÃ,´¦ÓÚÊÀ½çÁìÏÈˮƽ.µ«ÊÂÎï×ÜÊÇÒ»·ÖΪ¶þµÄ,°´ÕÕ·¢Õ¹µÄ¹Ûµã,ËüÒ²ÓÐ×ÅһϵÁв»×ãÖ®´¦,Ö÷ÒªÊÇ:Á÷³Ì½Ï³¤,ͬʱȫÁ÷³ÌΪ¿ª·ÅʽµÄ,ËùÓзÏË®¶¼ÊÇÖ±½ÓÅÅ·Å,»¯¹¤Ô­Áϲ»Äܵõ½ÓÐЧÀûÓÃ,ÓÉÓÚÉÏÊö²»×ã½øÒ»²½µ¼ÖÂ:
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×ÛÉÏËùÊöΪÁ˼õÉÙÈý·ÏÅÅ·Å,Ìá¸ß¾­¼ÃЧÒæÓбØÒª¿ª·¢¶ÌµÄ·â±ÕʽµÄÁ÷³Ì.
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2.
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¿¼Âǵ½ÏÖÐй¤ÒյķÏË®Ö÷ÒªÀ´×ÔÓÚÀë×Ó½»»»(»òÝÍÈ¡)¹ý³Ì,ͬʱÀë×Ó½»»»(»òÝÍÈ¡)¹ý³ÌµÄͶ×Ê´ó,²Ù×÷·ÑÓøß(Ô¼Õ¼APTÉú²úµÄ1/3×óÓÒ),Òò´Ë,¿ª·¢Ð¹¤ÒÕʱ,Ó¦½«Æä×÷Ϊ¼ò»¯µÄÖصã,ͬʱ´ÓÑ­»·¾­¼ÃµÄÔ­Ôò³ö·¢,NaOHµÄ»ØÊÕÀûÓÃÒàÓ¦ÈÏÕæ½â¾ö,½ü30ÄêÀ´,ÎÒ¹úÎÙÒ±½ð¼¼ÊõµÄ½ø²½,Ϊ½â¾öÉÏÊöÎÊÌâÌṩÁ˼¼Êõ»ù´¡,Ö÷ÒªÈçÏÂ:
(1)
¸ß¸Æ¿ó»ò°×ÎÙ¿ó¼î·Ö½â¹ý³ÌÔÓÖÊAs,P,Si,SnµÄÒÖÖÆ µÄÑо¿±íÃ÷[1],Ca(OH)2ÄÜÓëÈÜÒºÖеÄÔÓÖÊAs,P,Si,SnµÈ·´Ó¦,·Ö±ðÐγÉNaCaAsO4,Ca3(AsO4)2,Ca3(PO4)2,Ca5(PO4)3OH,CaSiO3,CaSnO3,CaSn(OH)6½øÈë³Áµí,ÆäÖ÷Òª·´Ó¦Îª:
2Na3AsO4(aq) + 3Ca(OH)2(s) = Ca3AsO42(s) + 6NaOH(aq)
Na3AsO4(aq) + Ca(OH)2(s) = NaCaAsO4(s) + 2NaOH(aq)
2Na3PO4(aq) + 3Ca(OH)2(s) = Ca3(PO4)2(s) + 6NaOH(aq)
3Na3PO4(aq) + 5Ca(OH)2(s) = Ca5(PO4)3OH(s) + 9NaOH(aq)
Na2SiO3(aq) + Ca(OH)2(s) = CaSiO3(s) + 2NaOH(aq)
Na2SnO3(aq) + Ca(OH)2(s) = CaSnO3(s) + 2NaOH(aq)
Na2SnO3(aq) + Ca(OH)2(s) +3H2O CaSn(OH)6(s) + 2NaOH(aq)
ÓÃÈ˹¤ÁÏÒºÊÔÑé±íÃ÷:½«Na3AsO4»òNa3PO4,Na2SiO3,Na2SnO3ÈÜÒºÓëCa(OH)2»ìºÏÔÚ160¡æÏ·´Ó¦2h,ÔòÈÜÒºÖÐ98%ÒÔÉϵÄAs,P,Si,Sn¶¼ÄÜÐγÉÉÏÊö²»ÈÜ»¯ºÏÎï½øÈë³Áµí.¹¤ÒµÉú²úʵ¼ùÖÐÒ²±íÃ÷¼î·Ö½â°×ÎÙ¾«¿ó»ò¸ß¸Æ¿óʱ,ÉéµÄÈܳöÂʽö2%~5%,²¢Ëæ¸Æº¬Á¿µÄÉý¸ß¶ø½µµÍ.
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Ϊ½øÐÐÎÙ¼î·ÖÀë,ÎÒ¹úÒÑÓгÉÊìµÄ¼¼Êõ,¼´½øÐÐŨËõ½á¾§,½«ÈÜÒºÖÐNaOHºÍWO3ŨËõµ½Ò»¶¨Å¨¶Èºó,Na2WO4¹ý±¥ºÍ½á¾§Îö³ö,ʵ¼ùÖ¤Ã÷ŨËõ½á¾§¹ý³Ì½«´øÀ´ÈçÏÂЧÒæ:
a.
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b.
ÔÚÎÙ¼î·ÖÀë¹ý³ÌÖÐ,ÔÓÖÊP,As,Si´ó²¿·Ö½øÈëÁ˼îĸҺ,¶øÔÚ·µ»Ø¼î·Ö½âʱ,ËüÃÇÓÖÓëCa(OH)2×÷ÓýøÈë¼î·Ö½âÔü,Òò¶øÓгýÔÓ×÷ÓÃ,¸ù¾Ýͳ¼Æ[2],½á¾§¹ý³ÌÄÜ´ÓNa2WO4ÖгýÈ¥Ò»°ëÒÔÉϵÄP,As,Si.Òò´Ë,ŨËõ½á¾§»ØÊÕNaOH¼ÈÊÇÒ»¸ö»ØÊÕ¼îµÄ¹ý³Ì,ÓÖÊÇÒ»¸ö½øÒ»²½È¥ÔÓÖʵĹý³Ì.
ÖÁÓÚÆä³É±¾,¾ÝÓйع¤³§µÄͳ¼Æ,²ÉÓüòµ¥µÄÕô·¢½á¾§¹øµÄÇé¿öÏÂ,»ØÊÕµÄNaOHµÄ¼ÛÖµ×ãÒÔµÖÏúÄܺÄ.ÈôÎüÊÕÖƼҵµÄ¾­Ñé[3],²ÉÓÃÈýЧ»òËÄЧÕô·¢,Ôò½«´øÀ´Ã÷ÏԵľ­¼ÃЧÒæ.
×ÛÉÏËùÊö,ÔÚ³ä·Ö·¢»Ó¼î·Ö½â¹ý³ÌºÍŨËõ»ØÊÕ¼î¹ý³ÌµÄÈ¥ÔÓÖÊ×÷ÓõĻù´¡ÉÏ,ËùµÃNa2WO4ÈÜÒºÖÐP,As,SiµÄº¬Á¿½«´ó·ù¶È½µµÍ,ʵ¼ùÖ¤Ã÷Ëü¿É½Ó½üþÑξ»»¯ÒÔºóµÄˮƽ,ijЩ¹¤³§µÄNa2WO4ÈÜÒºÖÊÁ¿ÓëþÑη¨ÒªÇó¶Ô±ÈÈç±í1Ëùʾ.
±í1 ijЩ¹¤³§Na2WO4ÈÜÒºµÄÖÊÁ¿ÓëþÑη¨ÒªÇó¶Ô±È
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A
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B
³§´¦ÀíÔÓ¿óŨËõ»ØÊÕNaOHºóµÄNa2WO4
(As/WO3)¡Á100
0.005~0.006
0.014
0.0078
(P/WO3)¡Á100
0.004~0.005
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(Si/WO3)¡Á100
0.02~0.03
0.5
0.05
3.
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4.
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(3)
È«Á÷³Ì»ù±¾·â±Õ.¹ý³ÌµÄË®ÈÜҺѭ»··µ»Ø,ÇÒÑ­»·Á¿Ò²ºÜÉÙ,Ö÷ÒªÅųöÎïÊǽþ³öÔüÒÔ¼°½á¾§Ä¸Òº»ØÊÕʱ²ú³öµÄÎÞ¹«º¦µÄÄÆÑÎ.ͬʱÓÉÓÚ»ù±¾ÉϱÕ·ѭ»·,Òò´ËΪÌá¸ßÎÙ×Ü»ØÊÕÂÊ´´ÔìÁËÓÐÀûÌõ¼þ.
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Ò×ÓÚʵʩ.Ïà¶ÔÓÚÏÖÐй¤ÒÕ¶øÑÔ,È«Á÷³ÌÔÚ¹¤ÒÕºÍÉ豸ÉϽöÊÇɾȥÀë×Ó½»»»»òþÑξ»»¯-ÝÍÈ¡¹ý³Ì,ÆäËû½öÊDzÙ×÷Öƶȵĸıä,Òò´Ë¾ø´ó²¿·Ö¹¤Ðò¿ÉÓÃÒÑÓеijÉÊì¼¼Êõ,É豸ÒàÎÞ´ó±ä»¯.
5.
Ö¸±ê¼°ÊÔ¼Á·ÑÓÃ
Õô·¢½á¾§Ê±µÄ½á¾§ÂÊÔ¼90%.
ÎÙ·Û»¹Ô­Ï´µÓµÄÖ±½Ó»ØÊÕÂÊÔ¼90%,¼ÓÈëÊÔ¼ÁµÄ·ÑÓÃԼΪÀë×Ó½»»»¹ý³ÌÊÔ¼Á·ÑµÄ80-90%×óÓÒ(δ¿¼ÂÇÌí¼Ó¼ÁµÄ»ØÊÕ,¿¼ÂÇÆä»ØÊÕʱÔò¸üµÍ).
6.
²úÆ·ÖÊÁ¿
ÏÖÒÔÆäÖмä²úÆ·"ÀàÀ¼ÎÙ"µÄÖÊÁ¿½üËƱíÕ÷²úÆ·µÄÖÊÁ¿.
(a)
Ô­ÁÏΪij³§ÀïÎÙ¾«¿ó·Ö½âĸҺ,ÆäÖк¬WO3218.7g/l,P 0.03g/l,As 0.03g/l,SiO2 0.5g/l,¾­Å¨Ëõ»ØÊÕ¼îºó,°´±¾¹¤ÒÕËùµÃ"ÀàÀ¼ÎÙ"µÄÔÓÖʺ¬Á¿Îª:Al 4;As 9;Bi 1;Ca 8;Co 1;Cr 1;Cu 3;Fe 9;K 9;Mg 7;Mn 10;Mo 40; Ni 6;P 6;Pb 1;S 6;Sb 8;Si 10;Ti 10;V 10;Sn 1,¹Ê³ýîâÍâÈ«²¿·ûºÏGB10116-88 APT-0¼¶±ê×¼.
(b)
Ô­ÁÏΪij³§´¦ÀíÄÑÑ¡Öпó¾­Å¨Ëõ»ØÊÕ¼îºóµÄNa2WO4¾§Ìå,ÆäÖÐ P/WO3 = 1.3¡Á10-4,As/WO3 = 0.78¡Á10-4,Si/WO3 5.2¡Á10-4.¾§ÌåÖ±½ÓÈܽâ,¼ÓÈëÌí¼Ó¼ÁA½øÐÐÕô·¢½á¾§,½á¾§ÂÊ90%×óÓÒ,ËùµÃ"ÀàÀ¼ÎÙ"³É·ÝΪ(ppm):Al 6;As 10;Bi 1;Ca <9; Co <5;Cr <10;Cu 3;Fe <9;Mg <5;Mn <5;Ni <5;Mo 50;Pb 1;Sb 3;Si 9;Sn 3;Ti <5;V <5.³ýAl,Mo,SnÍâÈ«²¿·ûºÏGB10116-88 APT-0±ê×¼.

8.
½áÂÛ.ÔÚ³ä·ÖÀûÓÃÎÙÒ±½ðÏÖÓм¼Êõ³É¹ûµÄ»ù´¡ÉÏ,¿ª·¢ÁËÒ»ÖÖ´ÓÎÙ¿óÎïÔ­ÁÏÖÆÈ¡ÎÙ·ÛµÄй¤ÒÕ,СÐÍÊÔÑé½á¹û³õ²½±íÃ÷¸Ã¹¤ÒÕ¾ßÓÐÁ÷³Ì·â±Õ,»·¾³Ð§ÒæºÃ,Ò×ÓÚʵʩµÈÌصã,Óдý½øÒ»²½Ôڽϴó¹æģϽøÐÐÑéÖ¤ºÍÓÅ»¯,²éÃ÷Æä²úÒµ»¯µÄ¿ÉÄÜÐÔ.

 

 

 

 

 

 

 


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